tweets

This is data scraped from swyx's timeline! See blog post

2 rows where favorited = 0, in_reply_to_screen_name = "andy_matuschak" and retweeted = 0

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id ▼ user created_at full_text retweeted_status quoted_status place source truncated display_text_range in_reply_to_status_id in_reply_to_user_id in_reply_to_screen_name geo coordinates contributors is_quote_status retweet_count favorite_count favorited retweeted possibly_sensitive lang scopes
1463727631669469184 swyx 33521530 2021-11-25T04:33:56+00:00 @andy_matuschak @danluu are substack’s leaderboards not a form of social proof and therefore distribution? curious about how you easily dismiss it       Twitter for iPhone 95f3aaaddaa45937ac94765e0ddb68ba2be92d20 0 [24, 146] 1456409147583336456 10724012 andy_matuschak       0 0 0 0 0   en  
1463928523429605384 swyx 33521530 2021-11-25T17:52:13+00:00 @andy_matuschak @danluu there’s a second hand effect going on - i dont look at the leaderboard myself, but every author that makes it on the leaderboard makes sure that everyone who follows them knows that they are on the leaderboard :) kinda like how i dont look at NYT Bestseller lists       Twitter for iPhone 95f3aaaddaa45937ac94765e0ddb68ba2be92d20 0 [24, 288] 1463927215289110529 10724012 andy_matuschak       0 0 1 0 0   en  

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CREATE TABLE [tweets] (
   [id] INTEGER PRIMARY KEY,
   [user] INTEGER REFERENCES [users]([id]),
   [created_at] TEXT,
   [full_text] TEXT,
   [retweeted_status] INTEGER,
   [quoted_status] INTEGER,
   [place] TEXT REFERENCES [places]([id]),
   [source] TEXT REFERENCES [sources]([id]), [truncated] INTEGER, [display_text_range] TEXT, [in_reply_to_status_id] INTEGER, [in_reply_to_user_id] INTEGER, [in_reply_to_screen_name] TEXT, [geo] TEXT, [coordinates] TEXT, [contributors] TEXT, [is_quote_status] INTEGER, [retweet_count] INTEGER, [favorite_count] INTEGER, [favorited] INTEGER, [retweeted] INTEGER, [possibly_sensitive] INTEGER, [lang] TEXT, [scopes] TEXT,
   FOREIGN KEY([retweeted_status]) REFERENCES [tweets]([id]),
   FOREIGN KEY([quoted_status]) REFERENCES [tweets]([id])
);
CREATE INDEX [idx_tweets_source]
    ON [tweets] ([source]);